Answer:
No.
Explanation:
Given that Kevin decides to soup up his car by replacing the car's wheels with ones that have 1.4 times the diameter of the original wheels. Note that the speedometer in a car is calibrated based on the tire's diameter and on the distance the tire covers in each revolution. (a) Will the reading of the speedometer change ?
Considering the formula
V = wr
Where
V = linear speed
W = angular speed
r = radius of the wheel.
But W = 2πrf
Where the the 2 and pi are constant. The radius of the first wheel will be small but counter balance with the larger frequency.
While the radius of the second wheel may be large but it will be of a small frequency.
We can therefore conclude that the reading on the speedometer will not change. Because speedometer will read the linear speed V.
Answer:
The electric flux though each face of the cube is 0.0942 Nm²/C.
Explanation:
The expression for the electric flux through the cuboid is given by:
Since, area of cuboid = 6a²
Where,
E is the electric field
a is the side of the cuboid
q is the charge
is the constant having value 8.85×10⁻¹² C²/Nm²
Thus, the expression for the electric flux through one face of the cuboid is given by:
So,
Given ,
q = 5.0×10⁻¹² C
Solving,
<u>The electric flux though each face of the cube is 0.0942 Nm²/C.</u>
<u></u>
Answer:
The question is not complete. see the complete question in the explanation section. The correct option is highlighted in bold
Explanation:
(a)A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. At the moment contact is made with the battery, the voltage across the resistor is
I. greater than the battery's terminal voltage.
II. equal to the battery's terminal voltage.
III. less than the battery's terminal voltage, but greater than zero.
IV. zero.
<em>Option (i) is not correct as the voltage across the resistor cannot be greater than the terminal voltage since the current is yet to flow through the resistor. Option (ii) is correct as both the resistor voltage and the terminal voltage will just equal at the instance of connection. Option (ii) can only be possible after the current must have passed through the resistor for a while not immediately after contact. Option (iv) is not correct, as this can only be possible is the contact is open.
</em>
(b)A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. At the moment contact is made with the battery the voltage across the capacitor is
I. greater than the battery's terminal voltage.
II. equal to the battery's terminal voltage.
III. less than the battery's terminal voltage, but greater than zero.
IV. zero.
<em>Option (i) is not correct as the capacitor is yet to charge talk less of the its voltage exceeding that of the battery. Option (ii) can only be correct if the capacitor is fully charged not when it has just been connected. Option (iii) can only occur if the capacitor is discharging. Option (iv) is the correct answer as the capacitor is about to start charging
</em>
Answer:
8.9*10^6 V/m
Explanation:
The expression for electric field strength E is given as
where V= voltage
d= distance of separation
Given data
substituting our given data into the electric field strength formula we have
