A 20-newton weight is attached to a spring.
1 answer:
Answer:
40 N/m
Explanation:
The diagram attached is used to answer the question
We know from Hooke's law that extension is directly proportional to the applied force hence
F=kx where x is extension, F is applied force and k is the spring constant. Making k the subject of the formula then
From the attached diagram extension is given by subtracting unstretched spring from stretched spring hence extension, x=1-0.5=0.5m
Substituting 20 N for F and 0.5 m for x then
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Answer:
Intensity = 11.56W/m²
The energy flowing through the given area is 4.55 J
Explanation:
The expression for the intensity of the electromagnetic wave is,
Here, is the permittivity of the free space,
is the electric field amplitude and
c is the speed of the light.
substitute
⁸m/s for c
8.85×10 −12 C²
/N⋅m² for
and 93.3 V/m for
The expression for the energy is,
E = I×A×t
Here, I is the intensity of the electromagnetic wave,
A is the area, and
t is the time.
Substitute
11.56W/m² for I
0.0287m ² for A
13.7s for t
The energy flowing through the given area is 4.55 J
The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.
<h3>What is the law of conservation of momentum?</h3>According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and m₂ will be u₁=5 and u₂=0 m/s respectively,
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
m₁u₁+m₂u₂=(m₁+m₂)v
M×5+3M×0=[M+3M]v
The final velocity is found as;
V=51.25 m/s
The velocity of block A is found as;
Hence, the final velocity of the block A will be 2.5 m/sec.
To learn more about the law of conservation of momentum, refer;
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