From rest, a rock is dropped from a garage roof. The roof is 6.0 meters above ground level. The rock will reach the earth at a speed of 10.849 meters per second.
<h3>What is velocity?</h3>
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity.
it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.
Given data:
V(Final velocity)=? (m/sec)
h(height)= 6.0 m
u(Initial velocity)=0 m/sec
g(gravitational acceleration)=9.81 m/s²
Newton's third equation of motion:
![\rm v_y^2 = u_y^2+ 2gh \\\\\rm v_y^2 = 0+ 2gh\\\\\ v_y= \sqrt{2\times 9.81 \ (m/s^2)\times 6.0 (m)} \\\\ v_y=10.849 \ m/sec](https://tex.z-dn.net/?f=%5Crm%20v_y%5E2%20%3D%20u_y%5E2%2B%202gh%20%5C%5C%5C%5C%5Crm%20v_y%5E2%20%3D%200%2B%202gh%5C%5C%5C%5C%5C%20%20v_y%3D%20%5Csqrt%7B2%5Ctimes%209.81%20%5C%20%28m%2Fs%5E2%29%5Ctimes%206.0%20%28m%29%7D%20%5C%5C%5C%5C%20v_y%3D10.849%20%5C%20m%2Fsec)
Hence, the velocity of the rock as it hits the ground will be 10.849 m/sec.
To learn more about the velocity refer to the link ;
brainly.com/question/862972
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