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jolli1 [7]
3 years ago
10

Triangle plz help me find B,b and c​

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

B = 55°

b = 17.1 (rounded to the nearest tenth)

c = 20.9 (rounded to the nearest tenth)

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Fill in the missing numbers<br>I need an answer ASAP<br><br>​
mamaluj [8]

Answer:

the missing numbers be 60 and 6 respectively

Step-by-step explanation:

The computation of the missing numbers are shown below:

Let us assume the missing numbers be x

a/

, \frac{1}{2} \times 30 =  \frac{1}{4} \times x\\\\15 =    \frac{1}{4} \times x\\\\x = 60

b.

\frac{1}{3} \times 12 =  \frac{2}{3} \times x\\\\4 =    \frac{2}{3} \times x\\\\x = 6

Hence, the missing numbers be 60 and 6 respectively

4 0
3 years ago
OK people stop putting your questions in the awnser box because you are just using poibts that can go to other people who actual
Lyrx [107]

Answer:

yes ma'am

Step-by-step explanation:

5 0
2 years ago
Please answer it’s 20 points for award!
guajiro [1.7K]

Answer:

The scale drawing is 20 units by 4 units

Step-by-step explanation:

20/5 = 4

100/5 = 20

6 0
2 years ago
What is the area of the figure? The figure is not drawn to scale.
lora16 [44]
Top triangle((6X9)/2)=27square 7x9=63 parallelogram 7X9=69 right triangle ((7X6)/2)=21 so 27+63+63+21=174
6 0
3 years ago
For bone density scores that are normally distributed with a mean of 0 and a standard deviation of​ 1, find the percentage of sc
gogolik [260]

Answer:

a) The percentage of bone density scores that are significantly high is 2.28%

b) The percentage of bone density scores that are significantly low is 2.28%

c) The percentage of bone density scores that are not significant is 95.44%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. significantly high​ (or at least 2 standard deviations above the​ mean).

This is 1 subtracted by the pvalue of Z = 2.

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of scores are signifcantly high

b. significantly low​ (or at least 2 standard deviations below the​ mean).

pvalue of Z = -2

Z = -2 has a pvalue of 0.0228

2.28% of scores are signicantly low.

c. not significant​ (or less than 2 standard deviations away from the​ mean).

pvalue of Z = 2 subtracted by the pvalue of Z = -2.

Z = 2 has a pvalue of 0.9772

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% of the scores are not significant

7 0
3 years ago
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