Answer:
Explanation:
velocity of sound in air at 20⁰C is 343 m /s
velocity of sound in water at 20⁰C is 1481 m /s
The wavelength of the sound is 2.86 m in the air so its frequency
= 343 / 2.86 = 119.93 .
This frequency of 119.93 will remain unchanged in water .
wavelength in water = velocity in water / frequency
= 1481 / 119.93
= 12. 35 m .
This is the diffraction. The longer the wavelength, the wider it spread. (The greater angle of the sector pattern formed)
Answer:
557.7Nm
Explanation:
We are given that
Radius,r=1.9 m
Angular speed,
Time,t=3.5 s
Initial angular velocity,
We have to find the large torque would have to be exerted .
Where
Substitute the values
Answer:
A. f = 8 Hz
B. T = 0.125 s
C. λ = 0.0166 m = 16.6 mm
D. d = 7.98 m
Explanation:
A.
The frequency of the wave can be given as:
<u>f = 8 Hz</u>
B.
The time period will be:
<u>T = 0.125 s</u>
C.
The wavelength is given as:
<u>λ = 0.0166 m = 16.6 mm</u>
D.
The distance traveled in 1 minute can be found out as follows:
<u>d = 7.98 m</u>