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vova2212 [387]
3 years ago
14

A small spaceship with a mass of only 2.6 ✕ 103 kg (including an astronaut) is drifting in outer space with negligible gravitati

onal forces acting on it. If the astronaut turns on a 12 kW laser beam, what speed will the ship attain in 1.0 day because of the momentum carried away by the beam?
Physics
1 answer:
vladimir1956 [14]3 years ago
6 0

Answer:

 v = 2.66 10⁻³ m/s

Explanation:

To work this problem we must use the relationship between the amount of movement and energy for an electromagnetic wave

    p = U / c

They give us the power of the laser, which is the relationship between work and time. Work is the variation of energy, in a laser beam that is an electromagnetic wave. We have its power

   P = W / t

   W = P t

Work is the variation of energy W = U

   p = P t / c

   ½ m v = P t / c

   v = 2 P t / m c

Let's reduce time to SI units

   t = 1.0 day (24 h / 1 day) (3600 s / 1 h) = 86400 s

Let's calculate

   v = 2 12 10³ 86400 / (2.6 10³ 3 10⁸)

   v = 2.66 10⁻³ m / s

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3 years ago
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A World-class sprinter can reach a top speed of about 11.5 m/s in the first 18.0 m of a race. What is the average acceleration o
irina [24]

Answer

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t = 3.13 s

Using the kinematic equations for the movement we have:


h(t) = P_{0} + Vot + \frac{1}{2}at ^ 2 (1)


V_{f} = V_{0} + at (2)


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t = time in seconds


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P_{0}=0


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V_{f} = 11.5\frac{m}{s}

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h (t) = 0.5at ^ 2\\h = 18 = 0.5at ^ 2

Then we clear "a" to find the acceleration.


\frac{36}{t^2} = a\\a = \frac{36}{(\frac{11.5}{a})^2} \\\\a =\frac{11.5^2}{36}\\a = 3.674 m / s ^2

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3 years ago
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Dahasolnce [82]

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A is false

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A is false.

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