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natta225 [31]
3 years ago
15

Harriet sells prints of her photographs, and is deciding what her minimum order should be during a sale. The equation that relat

es to her profit, y, from a minimum order of size x is 12x - 4y = 48.
Part A

What are the x-intercept and the y-intercept of the graph of her profit?

A. X-intercept: 3; y-intercept: -12
B. X-intercept: 4; y-intercept: 12
C. X-intercept: 4; y-intercept: -12
D. X-intercept: 3; y-intercept: 12


Part B

What should her minimum order size be, to make a profit?
Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
For part A, b is the answer
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neonofarm [45]

The amount of extra interest that will be paid is $24300

Since Nellie took out a car loan for $45,000 payable for 6 years at an interest rate of 15%, the interest that she will pay will be:

= ($45000 × 6 × 15) / 100

= $40500

On the other hand, if she hasn't applied for bankruptcy, the amount that she will pay will be:

= ($45000 × 6 × 6) / 100

= $16200

Therefore, the difference between the interest will be:

= $40500 - $16200

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The correct option is $24300. The given options are incorrect.

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2 years ago
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The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv
Rina8888 [55]

Answer:

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=14.42 represent the sample mean

\mu population mean (variable of interest)

\sigma=6.95 represent the population standard deviation

n=36 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

14.42-1.96\frac{6.95}{\sqrt{36}}=12.150    

14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690    

So on this case the 95% confidence interval would be given by (12.150;16.690)    

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If cos B is 4/5 what is sin a?​
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Answer:

sin(A+B)=sinAcosB+cosAsinB. Putting the values in. sin(A+B)=(4/5)(−3/5)+(3/5)(−4/5). sin(A+B)=−24/25.

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Solve for x.
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