Simplify 5x2(5x2− 3x − 1).

Mathematics

2 answers:

Leya [2.2K]4 years ago

4 0

I think the answer would be 25x^4-15x^3-5x^2

BaLLatris [955]4 years ago

3 0

The answer to your problem is........... 60..... i think :)

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Let x represent the measurment of an acute angle in degrees. the ratio of the complement of x to the supplement of x is 2: 5. gu

Nadusha1986 [10]

Ratio of complement of x : supplement of x
2 : 5
⇒ 2 times the supplement of x will be equal to 5 times the complement of x

5(90 - x) = 2 (180 - x)
450 - 5x = 360 - 2x
5x - 2x = 450 - 360
3x = 90
x = 30°

Complement of x = 90 - x = 90 - 30 = 60
Supplement of x = 180 - x = 180 - 30 = 150
Ratio:
60 : 150
60 ÷ 30 : 150 ÷ 30
2 : 5 (checked)

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3 years ago

Please help, thanks.

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Ahat [919]

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3 years ago

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$