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bagirrra123 [75]
3 years ago
15

Forested land in the area was cleared to make several building lots. Trees were left on the outskirts of each lot. This is a pic

ture of
one lot that has not sold, so there has been no house built. If the lot does not sell, predict how this area will look in another five
years.
A)
The land will be forested once again.
B)
The plot of land will be covered with grasses and flowers.
C)
The weeds will be replaced by woody shrubs and some small trees.
Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

C

Explanation:

The weeds will be replaced by woody shrubs and some small trees.

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A quantum of light has frequency of 1.8 x 10^14 Hz. Finds its energy.
SVETLANKA909090 [29]

Its energy : 1.193 x 10⁻¹⁹ J

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

\tt E=6.626\times 10^{-34}\times 1.8\times 10^{14}\\\\E=1.193\times 10^{-19}~J

3 0
3 years ago
What is the pH of a solution with [OH-] = 5.40 x 10-3 M?
igomit [66]
pH: 5.4E-3
pOH: 13.9946
[H+]: 0.987643022777
[OH-]: 1.01251158256E-14 acid
7 0
3 years ago
The number of electrons in the valence shell determine what types of bonds an atom can form.
Nataly_w [17]
This statement is right !
8 0
3 years ago
2.92 A 50.0-g silver object and a 50.0-g gold object are both added
Trava [24]

Answer:

82.9 mL  

Explanation:

1. Volume of silver

\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}

2. Volume of gold

\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}

3. Total volume of silver and gold

V = 4.766 mL + 2.591 mL = 7.36 mL

4 New reading of water level

V = 75.5 mL + 7.36 mL = 82.9 mL

3 0
4 years ago
Why homoannular diene in uv spectrometry have higher wavlenth than hetroannular diene?
Leno4ka [110]

Answer:

Homoanular dienes have a greater base value than heteroanular dienes

Explanation:

Woodward in 1945 gave a set of rules relating the wavelength of maximum absorption to the structure of a compound. These rules were modified by Fieser in 1959. These sets of rules describe the absorption of organic molecules in the UV region of the electromagnetic spectrum.

Each system of diene or triene has a given fixed value at which maximum absorption is expected to occur according to Woodward rules. This given fixed value is called the base or parent value. If the two double bonds are trans to each other, the diene is said to be transoid. If the two double bonds belong to different rings, the system is said to be heteroanular and the base value in each case is 215nm. If the double bonds are cis to each other (cisoid), or the two double bonds are in the same ring (homoanular), then the base value is 253nm.

Since λmax = base value + ∑ substituent contributions + ∑ other contributions, if the other contributions are not very significant, homoanular diene will have a greater λmax because of its larger base value compared to heteroanular diene. This correlates well with the fact that conjugated systems absorb at a longer wavelength.

4 0
3 years ago
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