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Nata [24]
3 years ago
6

How will an increase in pressure affect the following chemical equilibrium:

Chemistry
2 answers:
tresset_1 [31]3 years ago
8 0

Answer:

Will up 2NO

Explanation:

The future gas particle will be increased by about 4.2. (estimated) Pressure is absorbed, and by the gas, created heavier.

zzz [600]3 years ago
8 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>Amount</u><u> </u><u>of</u><u> </u><u>NOCl</u><u> </u><u>yielded</u><u> </u><u>increases</u>

Explanation:

There is increase in volume following the forward reaction. When volume increases, there will be decrease in pressure for the forward reaction.

When pressure increases, backward reaction is favoured hence amount of NOCl produced increases whereas NO and Cl decreases.

.

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⦁ Find the concentration of H+, OH-, PH and POH of 0.03 M of magnesium hydroxide which ionizes to the extent of only 1 /3 in aqu
lions [1.4K]

Answer:

pH=12.3\\\\pOH=1.7\\

[H^+]=5x10^{-13}M

[OH^-]=0.02M

Explanation:

Hello there!

In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

Mg(OH)_2(s)\rightleftharpoons Mg^{2+}(aq)+2OH^-(aq)

Thus, since the ionization occurs at an extent of 1/3, we can set  up the following relationship:

\frac{1}{3} =\frac{x}{[Mg(OH)_2]}

Thus, x for this problem is:

x=\frac{[Mg(OH)_2]}{3}=\frac{0.03M}{3}\\\\x=  0.01M

Now, according to an ICE table, we have that:

[OH^-]=2x=2*0.01M=0.02M

Therefore, we can calculate the H^+, pH and pOH now:

[H^+]=\frac{1x10^{-14}}{0.02}=5x10^{-13}M

pH=-log(5x10^{-13})=12.3\\\\pOH=14-pH=14-12.3=1.7

Best regards!

4 0
3 years ago
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Answer:

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