We will first calculate the concentration of sodium hydroxide, knowing the massive K hp. That was required to neutralize the 22.65 ml of sodium hydroxide solution. So the polarity sodium hydroxide will be take the massive K HP divided by its molar mass to get moles K HP. Then recognize one mol K HP reacted with one mole sodium hydroxide. Now we have mold sodium hydroxide to get concentration. We simply multiply by the leader volume of the sodium hydroxide solution. 22.65 ml is .02265 L. And we get a polarity of zero 0.3351 Molar sodium hydroxide. Now to calculate the concentration of hcl, we need to know the molds hcl divided by the volume of the hcl solution. To get the moles. Hcl will take the 25 ml of sodium hydroxide used in the tight rations converted to leaders. 25 ml is .02500 l multiply that by the concentration of sodium hydroxide that we just determined up here to get mold sodium hydroxide, then convert moles sodium hydroxide into molds. Hcl, recognizing it's a 1 to 1 molar relationship. Now that we have moles hcl, we just divide by the leaders of the hcl solution that was titrate, id 0.2. Sorry, 23.35 mL is 0.2335 liters. And we get a concentration of 0.3588 molar hcl. I hope that helps
