Plsss help I’ll give u brainlest and 10 points

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

3 years ago

Dont understand please help easy 20pts

nlexa [21]

Answer:

The answer is G. y=2x-2

Step-by-step explanation:

y+6=2(x+2)

First you multiply 2 by what is in the parenthesis

y+6=2x+4

Next you get y by itself by subtracting 6

y=2x+4-6

Simplify

y=2x-2

4 0

3 years ago

Pls help ASAP! I will mark the brainliest (IF I GET IT RIGHT)

Gelneren [198K]

Answer:

V=288π

288*3.14=904.32

Step-by-step explanation:

V=4/3π $(6)^{3}$

V=4/3π 216

V=4π72

V=288π

288*3.14=904.32

4 0

2 years ago

Find the value of X PLEASE

Oliga [24]

Answer:

x ≈ 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Trigonometry

Law of Cosines: a^2 = b^2 + c^2 - 2(b)(c)cosA

a is a side length
b is a side length
c is a side length
A is an angle corresponding with side a

Step-by-step explanation:

Step 1: Define

a = x

A = 30°

b = 16

c = 30

Step 2: Solve for x

Substitute: x² = 16² + 30² - 2(16)(30)cos30°
Exponents: x² = 256 + 900 -2(16)(30)cos30°
Evaluate: x² = 256 + 900 -2(16)(30)(√3/2)
Multiply: x² = 256 + 900 - 480√3
Add: x² = 1156 - 480√3
Subtract: x² = 324.616
Isolate x: x = √324.616
Evaluate: x = 18.0171
Round: x ≈ 18

3 0

2 years ago

90<-30p+15 how do you solve this

Alenkinab [10]

*To solve an inequality, it's the same as if you were solving an equation: Isolate the desired variable to one side to solve.

Firstly, subtract 15 on both sides: $75$

Next, you are going to divide both sides by -30. Since you are dividing by a negative, you are going to flip the inequality symbol. Your final answer will be: $-\frac{5}{2}>p$ 

3 0

3 years ago