<span>.2 times 60 equals your answer</span>
Least to greatest
1.04, 1.0494, 1.2, 1.33
Simplifying
5C + -4 + -2C + 1 = 8C + 2
Reorder the terms:
-4 + 1 + 5C + -2C = 8C + 2
Combine like terms: -4 + 1 = -3
-3 + 5C + -2C = 8C + 2
Combine like terms: 5C + -2C = 3C
-3 + 3C = 8C + 2
Reorder the terms:
-3 + 3C = 2 + 8C
Solving
-3 + 3C = 2 + 8C
Solving for variable 'C'.
Move all terms containing C to the left, all other terms to the right.
Add '-8C' to each side of the equation.
-3 + 3C + -8C = 2 + 8C + -8C Combine like terms: 3C + -8C = -5C<span>-3 + -5C = 2 + 8C + -8C
Combine like terms: 8C + -8C = 0
-3 + -5C = 2 + 0
-3 + -5C = 2
Add '3' to each side of the equation.
-3 + 3 + -5C = 2 + 3
Combine like terms: -3 + 3 = 0
0 + -5C = 2 + 3
-5C = 2 + 3
Combine like terms: 2 + 3 = 5
-5C = 5
Divide each side by '-5'.
C = -1
Simplifying
C = -1</span>
Given :
On a number line, suppose the coordinate of A is 0, and AR = 15.
To Find :
the possible coordinates of the midpoint of AR.
Solution :
Their can be two points R which is at a distance of 15 units from the A .
One is -15 and other is 15.
Now, mid-point of A(0) and R(-15) is M (-7/2).
Also, mid-point of A(0) and R(15) is M (7/2).
Therefore, possible coordinates of the midpoint of AR is 7/2 , -7/2.
Hence, this is the required solution.
