Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
Answer:
Step-by-step explanation:
We are given that
Loretta grew watermelons in her garden last year=54
We have to find the expression which shows the number of watermelons Loretta grew this year.
To find the expression which shows the number of watermelons Loretta grew this year by adding watermelons grew in her garden last year and number of watermelons increased .
According to question
5/9 of 54=
Therefore, the expression which shows the number of watermelons Loretta grew this year
=
Answer:
3x - 6
Step-by-step explanation:
To evaluate f(2x) and f(x + 2) substitute x = 2x and x = x + 2 into f(x)
f(2x) = 3(2x) - 2 = 6x - 2
f(x + 2) = 3(x + 2) - 2 = 3x + 6 - 2 = 3x + 4
Thus
f(2x) - f(x + 2)
= 6x - 2 - (3x + 4)
= 6x - 2 - 3x - 4
= 3x - 6
