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3 years ago

A rocket is being launched straight up. Air resistance is not negligible.

2 answers:

7 0

A rocket is launching upwards. The force acting on the rocket to move upward is F. The forces acting opposite to thrust are weight and drag force. The drag force is due to the air resistance. In order to move upwards the thrust force must be greater than weight and drag force. Figure shows the free body diagram of rocket at the time of launching.There are only three forces: weight (always present), thrust (provided from the rocket’s engines to lift it up) and air resistance (said specifically to be not negligible). There are no horizontal forces.

Yanka [14]3 years ago

3 0

Answer:

hope this will help you

have a great day

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A scientist collected the following data, which show how the pressure of water vapor changes with temperature.

den301095 [7]

Answer:

Make a graph for better visual representation.

Explanation:

Presenting data like that would require someone to see the increase. The best way would be a graph to be shown, to really show the impact by the line going up in the graph.

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3 years ago

Read 2 more answers

A horizontal spring on a frictionless surface has a spring constant of 10 N/m with a mass of 2kg attached to the end of the spri

Alex

Answer:

0.356 times the mass pass through equilibrium per second.

Explanation:

Given that,

Spring constant = 10 N/m

Mass = 2 kg

Stretched spring = 2m

We need to calculate the frequency

Using formula of frequency

$f=\dfrac{1}{2pi}\sqrt{\dfrac{k}{m}}$

Where, m = mass

k = spring constant

Put the value into the formula

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{10}{2}}$

$f=0.356\ Hz$

We know that,

Hertz = cycle per second

Hence, 0.356 times the mass pass through equilibrium per second.

4 0

3 years ago

If a proton and an electron are released when they are 6.50×10⁻¹⁰ m apart (typical atomic distances), find the initial accelerat

Cerrena [4.2K]

Answer:

(a) Acceleration of electron= 5.993×10²⁰ m/s²

(b) Acceleration of proton= 3.264×10¹⁷ m/s²

Explanation:

Given Data

distance r= 6.50×10⁻¹⁰ m

Mass of electron Me=9.109×10⁻³¹ kg

Mass of proton Mp=1.673×10⁻²⁷ kg

Charge of electron qe= -e = -1.602×10⁻¹⁹C

Charge of electron qp= e = 1.602×10⁻¹⁹C

To find

(a) Acceleration of electron

(b) Acceleration of proton

Solution

Since the charges are opposite the Coulomb Force is attractive

$F=\frac{1}{4(\pi)Eo }\frac{|qp*qe|}{r^{2} }\\ F=(8.988*10^{9}Nm^{2}/C^{2})*\frac{(1.602*10^{-19})^{2} }{(6.50*10^{-10} )^{2} } \\F=5.46*10^{-10}N$

From Newtons Second Law of motion

F=ma

a=F/m

For (a) Acceleration of electron

$a=F/Me\\a=(5.46*10^{-10} )/9.109*10^{-31}\\ a=5.993*10^{20}m/s^{2}$

For(b) Acceleration of proton

$a=F/Mp\\a=(5.46*10^{-10} )/1.673*10^{-27} \\a=3.264*10^{17}m/s^{2}$

3 0

3 years ago

Can someone please help me match these up

yaroslaw [1]

Answer:

you need to give the answers choices

Explanation:

4 0

3 years ago

F. Protons and neutrons

Readme [11.4K]

Answer:

2. False :

An object that is positively charged has a greater positive charge and a lower negative charge.

3. Will be This :

Q.→ TRUE or FALSE: An object that is negatively charged could contain only electrons with <u>no</u> accompanying protons.

Answer → False :

Negatively charged objects have protons; it's just their number of electrons is greater than their number of protons.

4. False :

An object that is electrically neutral contains neutrons and the same number of unlike charges, i.e., electrons and protons.

3 0

3 years ago