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beks73 [17]
2 years ago
12

The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.

Physics
1 answer:
Sholpan [36]2 years ago
8 0

The frequency of rotation of Mars is 0.0000113 Hertz.

<u>Given the following data:</u>

  • Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

<u>Conversion:</u>

1 day = 24 hours

24 hours to minutes = 60 × 24 = 1440 minutes

1440 + 37 = 1477 \; minutes

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

X = 60 × 1477

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}

<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

Read more: brainly.com/question/14708169

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A 0.950 kg block is attached to a spring with spring constant 16.0 N/m . While the block is sitting at rest, a student hits it w
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Answer:

Explanation:

Given that,

Mass attached m = 0.95kg

Spring constant k = 16N/m

Instantaneous speed v = 36cm/s = 0.36m/s

Amplitude A=?

When x = 0.7A

Using conservation of energy

∆K.E + ∆P.E = 0

K.E(final) — K.E(initial) + P.E(final) — P.E(initial) = 0

At the beginning immediately the hammer hits the mass, the potential energy is 0J, Therefore, P.E(initial) = 0J, so the speed is maximum.

Also, at the end, at maximum displacement, the speed is zero, therefore, K.E(final) = 0

So, the equation becomes

— K.E(initial) + P.E(final) = 0

K.E(initial) = P.E(final)

½mv² = ½kA²

mv² = kA²

0.95 × 0.36² = 16×A²

0.12312 = 16•A²

A² = 0.12312/16

A² = 0.007695

A = √0.007695

A = 0.088 m

A = 8.8cm

B. Speed at x = 0.7A

Using the same principle above

K.E(initial) = P.E(final)

½mv² = ½kA²

Where A = 0.7A = 0.7 × 0.088 = 0.0614m

Then,

½× 0.95 × v² = ½ × 16 × 0.0614²

0.475v² = 0.0310644

v² = 0.0310644/0.475

v² = 0.0635

v = √0.0635

v = 0.252 m/s

v = 25.2 cm/s

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3 years ago
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Answer:

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Explanation:

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85) List and discuss the structures of a long bone. 86) Discuss the organization of the five regions of the spine. 87) Explain h
Lisa [10]
85)
The bone structure from outside would be periosteum, cortical, cancellous then medulla. Periosteum is the area outside the bone that will supply nutrition into the outer part of the bone. Cortical is the layer where bone mineral deposition is intense. In this part, the bone is compact and hard. This is the part of the bone that has great strength.
Cancellous is part of the bone where it is not too hard but not too soft. Mineralization is not so dense like cortical layer. That makes this part looks spongy. 
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86)
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87)
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This effect makes the neck can turn to side easily. It also makes neck more mobile vertically, make a nodding movement is possible.
88)
Thre kind of joints would be: Synarthrosis, amphiarthrosis, and diarthrosis.
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