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PSYCHO15rus [73]
3 years ago
13

A space explorer is moving through space far from any planet or star. He notices a large rock, taken as a specimen from an alien

planet, floating around the cabin of the ship. Should he push it gently, or should he kick it toward the storage compartment? Explain.
Physics
1 answer:
yaroslaw [1]3 years ago
3 0
He should push it gently.
This is because the forces of resistance this situation are minimal, so the rock will not slow as it would on Earth. Kicking the rock may result in it travelling too fast and hitting something else, causing damage. Moreover, the rock could start rebounding off of surfaces and create havoc. 
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Answer:

t = 6.17 s

Explanation:

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If the wheel starts from rest, w_{0} = 0 rad/s

The angular displacement of the wheel can be given by the formula:

\triangle \theta = \omega_0 t + 0.5 \alpha t^2................(1)

Where \alpha is the angular acceleration

\tau = I \alpha\\\alpha = \frac{\tau}{I} \\\alpha = 50/150\\\alpha = 0.33 rad/s^2

To get t, put all necessary parameters into equation (1)

2\pi = 0(t) + 0.5(0.33)t^2\\2\pi =0.5(0.33)t^2\\t^2 = \frac{4 \pi}{0.33} \\t^2 = 38.08\\t = 6.17 s

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Answer:

7.0\cdot 10^{-13}C

Explanation:

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F=k\frac{q_1 q_2}{r^2}

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In this problem, we have:

r=0.070 cm =7\cdot 10^{-4} m is the distance between the charges

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F=9.0\cdot 10^{-9}N is the force between the charges

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F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(9.0\cdot 10^{-9})(7\cdot 10^{-4})^2}{8.99\cdot 10^9}}=7.0\cdot 10^{-13}C

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Answer:

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