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Ne4ueva [31]
3 years ago
7

WILL MARK BRAINIEST IF RIGHT

Mathematics
2 answers:
4vir4ik [10]3 years ago
5 0

Answer:

The answer is A

kirill115 [55]3 years ago
4 0

Answer:

C

Step-by-step explanation:

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Can someone do 15?!?!?
andrew-mc [135]

<u>Given</u>:

The given triangle is a right triangle.

The length of the hypotenuse is 31 units.

The length of the leg is 23 units.

One of the angle is x.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting \theta=x, the side opposite to the angle x measures 23 units and the hypotenuse is 31.

Thus, we have;

sin \ x=\frac{23}{31}

Dividing, we get;

sin \ x=0.74

Taking sin ^{-1} on both sides of the equation, we get;

x=sin^{-1}(0.74)

x=47.7

Rounding off to the nearest whole integer, we get;

x=48

Thus, the value of x is 48°

Hence, Option c is the correct answer.

5 0
3 years ago
Write two integers with different signs that have a sum of -25.
Scilla [17]

Answer:

1.

-25+0

-30+5

2.

-15-10

-20-5

3 0
3 years ago
ABC DEF<br><br><br><br><br> AB corresponds to DF.<br> True<br> False
Alex Ar [27]

it's false

I guess

have a nice day

6 0
3 years ago
Read 2 more answers
PLZ help<br> solve for x
Alika [10]

Answer:

X = - 6                                                                                                                                

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
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