Answer:
Methods of soil conservation are listed below.
Explanation:
The major sources of soil erosion include water,wind and tillage. In order to mitigate or prevent soil erosion, some of the following techniques can be implemented:
- <u>Contour Farming: </u>Planting in row patterns that run level around a hill — as opposed to the up and down the slope pattern.This reduces runoffs and consequently water erosion.
- <u>Crop Rotation:</u> This involves planting crops with high residue (e.g corn, small grains, e.t.c) in rotation,as the layer of residue would protect the topsoil.
- <u>Built in structural diversion</u> : Used often for gully control, to regulate flow of water away from the field and through designated desired paths.
- <u>Conservation Tillage</u>: This involves methods such as no-till planting, strip rotary tillage, etc, which do not allow the soil surface to be smooth and bare, but instead covered with crop residue that protects the soil from eroding forces.
Answer:
The correct option is;
It is used during photosynthesis to capture sunlight
Explanation:
During photosynthesis, light energy from the Sun is converted and stored in sugars as chemical energy. The Sun light energy is used in the formation of complex sugars such as glucose from the combination of water from the ground and carbon dioxide from the atmosphere while oxygen is released as the byproduct. Organisms are then able to obtain energy from the glucose as well as carbon fiber
The chemical equation for the reaction is as follows;
6CO₂ + 12H₂O + light energy → C₂H₁₂O₆ + 6O₂ + 6H₂O
Carbon, Water, GLucose, Oxygen, Water
dioxide
Answer:
We say that the solution is unsaturated.
Explanation:
If the salt solubility is 36 g in 0.1 L of water then we can dissolve 360 g of salt in 1 L of water.
Because the solution contains 200 g of salt in 1 L of water, the solution is unsaturated because more salt can be added until we reach the saturation point.
We call the solution dilute when we compare the concentration of a solution with the concentration of another solution, but here we do not compare different solutions.
Answer:
Explanation:
This is an example of a limiting reactant question, and is very common as a general chemistry problem.
We first see the balanced equation, that is:
2CuCl2+4KI→2CuI+4KCl+I2
We first need to find the limiting reactant
We see that 0.56 g of copper(II) chloride (CuCl2) reacts with 0.64 g of potassium iodide (KI) . So, let's convert those amounts into moles.
Copper(II) chloride has a molar mass of
134.45 g/mol . So in 0.56 g of copper(II) chloride, then there exist
0.56g134.45g/mol≈4.17⋅10−3 mol
Potassium iodide has a molar mass of
166 g/mol . So, in 0.64 g of potassium iodide, there exist
if it wrong i am sorry
Answer:
Alternative Titles: nuclear force, strong interaction, strong nuclear force. Strong force, a fundamental interaction of nature that acts between subatomic particles of matter. The strong force binds quarks together in clusters to make more-familiar subatomic particles, such as protons and neutrons.
