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Orlov [11]
3 years ago
13

True or false silica is the most abundant compound found in magma.

Chemistry
1 answer:
Burka [1]3 years ago
3 0
 your answer is true because it is found iin the magma
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As the temperature of one of the four liquids increases, the vapor pressure will
s2008m [1.1K]

Answer:

a) increase exponentially.

Explanation:

The vapor pressure is depend only on temperature.

The vapor pressure of liquid does not depend upon amount of liquid. For example whether the liquid is 50 g or 30 g its vapor pressure will remain same according to the temperature.

The temperature and vapor pressure have exponential relationship. As the temperature of liquid increases its vapor pressure also goes to increase. When the temperature of liquid goes to decrease its vapor pressure also decreases.

The change in vapor pressure of substance when temperature changes is given as,

ln P₂/P₁ = ΔH(va)/R (1/T₁ - 1/T₂)

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3 years ago
What are the factors that affect the rate of dissolution? color, temperature, stirring texture, surface area, stirring temperatu
tangare [24]
Color, temperature, stirring
3 0
3 years ago
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____B₂Br₆ + ___HNO₃ ---->___B(NO₃)₃ + ____HBr balance them thanks!!!
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1, 6, 2, 6
In the order you wrote them in
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6 0
3 years ago
Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno
melamori03 [73]

1.062 mol/kg.

<em>Step 1</em>. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

<em>Step 4</em>. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

<em>Step 5</em>. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

<em>Step 6</em>. Calculate the molal concentration of the NaOH

<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

3 0
3 years ago
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