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arsen [322]
3 years ago
7

Which group is likely to react with chlorine to form compounds in the form xcl?

Chemistry
1 answer:
Umnica [9.8K]3 years ago
4 0
Group 1 elements since they have one outermost electron which they can give to chlorine which has 7 outermost electrons in order to form a stable compound.

Example 
Pottasium (K) + Chlorine (Cl) = Potassium Chloride (KCL)
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Acetanilide has a solubility of 1.00 g/185 ml in 25 oc water and 1.00 g/20 ml in 100 oc water. what is the minimum volume of wat
Likurg_2 [28]

In the crystallization process the solid compound is dissolved in the solvent at elevated temperature and the crystallize product obtained by slow cooling of the  solution. Here the solubility of acetanilide at 100°C is 1g per 20mL of water. Thus to dissolve 500mg of acetanilide at high temperature that is 100°C we need 10mL of water.

Now at 25°C after the re-crystallization there will be some amount of dissolve acetanilide. Which can be calculated as- 185mL of water is needed to dissolve 1g or 1000mg of acetanilide at 25°C. Thus in 10mL of water there will be \frac{10X1000}{185}=54.05gmg of acetanilide.    

6 0
4 years ago
How are catapults an example of a third class lever? Please explain!
Katen [24]
I hope that you can understand this!!! Lol

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3 0
3 years ago
What is a liquid mixture whose parts are evenly blended?.
Eva8 [605]

Answer:

A homogeneous mixture is a type of mixture in which the individual substances are evenly mixed.

Explanation:

3 0
2 years ago
Which statement applies to transverse waves?
11Alexandr11 [23.1K]

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the waves have a trough

Explanation:

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6 0
3 years ago
Read 2 more answers
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
4 years ago
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