All categories

1 year ago

Thanks for the answer

Mathematics

1 answer:

iragen [17]1 year ago

4 0

Answer:

12 books

Step-by-step explanation:

30 multiply by 2/5=12 books that were sold to co-workers.

3/5 which is the remainder multiplied by 1/2 =3/10

3/10 multiply by 30 =6 books sold to her neighbours

now that 30 is the original subtract12 +6

You might be interested in

HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-

Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

$f(x) =2x^3-9x^2+13x-6$

If x+1 is a factor , then f(-1) must evaluate to zero.

$f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6$

$f( - 1) =2( - 1)-9( 1)+13( - 1)-6$

$f( - 1) = - 2-9 - 13-6$

$f( - 1) = -11 - 19$

$f( - 1) = - 30$

Since f(-1) is not equal to zero, x+1 is not a factor of

$f(x) =2x^3-9x^2+13x-6$

6 0

3 years ago

Y=-x^2+2x+10 y=x+2 Substitution Please show your work Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

Find the values of y

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

2 years ago

Two numbers are between 10 and 20. Their greatest common factor is 3. Which two numbers could they be?

alina1380 [7]

Answer:

12 and 15 or

12 and 18 or

15 or 18

Step-by-step explanation:

The two numbers have to both be divisible by 3, since their greatest common factor is 3. This only leaves..

12, 15, or 18 (no other numbers between 10 and 20 are divisible by 3)

The factors of 12 are: 2, 3, 4, 6, and 12

The factors of 15 are: 3, 5, and 15

The factors of 18 are: 2, 3, 6, 9, and 18

All three numbers have 3 as a greatest common factor, so we have 3 pairs of numbers they could be...

12 and 15 or

12 and 18 or

15 or 18

4 0

2 years ago

Please help question in picture

svet-max [94.6K]

Answer:

A:29

Step-by-step explanation:

3 0

2 years ago

How many solutions does y=-6x-9 have

Oksanka [162]

Answer:

an infinite number

Step-by-step explanation:

This equation has a graph that is a line. Every point on the line is a solution.

There are an infinite number of solutions.

7 0

2 years ago