I think it is 32, bc the value of x is 20 so your problem would look like this; 2 ( (20) - 4 )
Complete question is;
How many 10 - digit numbers are there, such that the sum of the digits is divisible by 2?
Answer:
There are 4500000000 ten digit numbers whose sum is divisible by 2.
Step-by-step explanation:
Since we are dealing with 10 digit numbers, the first 10 digit number whose sum is divisible by 2 is; 1000000001.
While the last 10 digit number whose sum is divisible by 2 is 9999999999.
Now,to find how many 10 digit numbers whose sum are divisible by 2, we will simply divide the difference of both numbers by 2 and then add 1 to the answer. This is because subtracting the minimum from the maximum gives us the number of 10 digit numbers we have. Then dividing by 2 gives the number of ten digit numbers with sum divisible by 2 in between. Then adding 1 to the result to cover the number not included gives;
((9999999999 - 1000000001)/2) + 1 = 4500000000
Answer:
Let's factor x2+3x−18
x2+3x−18
The middle number is 3 and the last number is -18.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 3
Multiply together to get -18
Can you think of the two numbers?
Try -3 and 6:
-3+6 = 3
-3*6 = -18
Fill in the blanks in
(x+_)(x+_)
with -3 and 6 to get...
(x-3)(x+6)
Answer:
(x−3)(x+6)
Step-by-step explanation:
To get to 20 minutes from 2 minutes you multiply by 10, do the same to the 30 problems to get 300. The answer is 300 problems in 20 minutes.
Answer:
Sum equation: x + y = 29
Difference equation: x - y = 13
