Answer: <span>Hydraulic Fracturing
</span>
Hydraulic Fracturing is also referred as Fracking. In this process, r<span>ock is fractured with the help of pressurized liquid. It involves injecting highly pressure fracking fluid, which is primarily water. It also contains sand or other</span><span> suspended particles.</span><span> Fracking fluid</span><span> cracks down deep-rock formations, resulting in free flow of </span>natural gas<span>, </span>petroleum<span>, and </span>brine<span>. </span>
Answer:
51.17g of Cl2O7
Explanation:
The equation for the reaction is given below:
Cl2O7 + H2O → 2HClO4
First, let us calculate the masses of Cl2O7 and HClO4 from the balanced equation. This is illustrated below:
Molar Mass of Cl2O7 = (2x35.5) + (16x7) = 71 + 112 = 183g/mol
Molar Mass of HClO4 = 1 + 35.5 + (16x4) = 1 + 35.5 + 64 = 100.5g/mol
Mass of HClO4 from the balanced equation = 2 x 100.5 = 201g
Now, we can obtain the mass of Cl2O7 that must react to form 56.2g HClO4. This is illustrated below:
From the equation above,
183g of Cl2O7 reacted to produced 201g of HClO4.
Therefore, Xg of Cl2O7 will react to produce 56.2g of HClO4 i.e
Xg of Cl2O7 = (183 x 56.2)/201
Xg of Cl2O7 = 51.17g
From the calculations made above, 51.17g of Cl2O7 is required to produce 56.2g of HClO4
Answer:
1.119 liters
Explanation:
There are 1000 millileters in 1 liter.
There are 1119 ml in this problem
Since we know that there are 1000 ml per 1 liter, we must divide the amount of millileters by 1000
1119 ÷ 1000 = 1.119 liters
12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
12 * 125 / 100 = 15 g of salt is present in 125 g mixture.
b. The amount of sand can be calculated similarly, 88 %
of 125 g is 88 * 125 / 100 = 110 g of sand is present in
125 g mixture.