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3 years ago

An object accelerates 8.2 m/s2 when a force of 20.1 Newton's is applied to it. What is the mass of the object?

2 answers:

5 0

Hey it's me again haha!

the answer to your question is:

answer: so f=20.1

a=8.2

m=?

f=ma

20.1 = 8.2*m in

20.1/8.2=m

so the answer is around 2.45 something!
also i'm sorry this question had be stumbled!

tresset_1 [31]3 years ago

4 0

<u>We are given:</u>

Acceleration of the object (a) = 8.2 m/s²

Force applied on the object (F) = 20.1 newtons

Mass of the object (m) = m kg

<u></u>

<u>Solving for the mass of the object:</u>

From newton's second law of motion:

F = ma

<em>replacing the variables</em>

20.1 = m * 8.2

m = 20.1/8.2

m = 2.45 kg

Hence, the object weighs 2.45 kg

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Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s

Rate in terms of disappearance of $O_2$ = $-\frac{1d[O_2]}{dt}$

Rate in terms of appearance of $NO_2$ = $\frac{1d[NO_2]}{2dt}$

1. The rate of formation of $NO_2$

$-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}$

$\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s$

2. The rate of disappearance of $O_2$

$-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}$

$-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

Learn more about rate law

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3 years ago

2. Why do you think electroplated jewelleries are in demand?<br> Chemistry plsss

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2 years ago

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Answer:

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The elements in this group have the highest electronegativity values.
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