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ella [17]
3 years ago
8

An object accelerates 8.2 m/s2 when a force of 20.1 Newton's is applied to it. What is the mass of the object?

Chemistry
2 answers:
Shalnov [3]3 years ago
5 0
Hey it's me again haha!

the answer to your question is:

answer: so f=20.1

a=8.2

m=?

f=ma

20.1 = 8.2*m in

20.1/8.2=m

so the answer is around 2.45 something!
also i'm sorry this question had be stumbled!
tresset_1 [31]3 years ago
4 0

<u>We are given:</u>

Acceleration of the object (a) = 8.2 m/s²

Force applied on the object (F) = 20.1 newtons

Mass of the object (m) = m kg

<u></u>

<u>Solving for the mass of the object:</u>

From newton's second law of motion:

F = ma

<em>replacing the variables</em>

20.1 = m * 8.2

m = 20.1/8.2

m = 2.45 kg

Hence, the object weighs 2.45 kg

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Explanation:

Given data:

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4 0
2 years ago
What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n
ANEK [815]

<u>Answer:</u> The volume of permanganate ion (potassium permanganate) is 10.0 mL

<u>Explanation:</u>

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\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

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Volume of solution = 20.0 mL = 0.020 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol

For the given chemical equation:

5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = \frac{1}{5}\times 0.00762=0.00152mol of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

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Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

3 0
3 years ago
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