Given: g on moon = –1.63 meters/second2

Will a precipitate (ppt) form when 20.0 mL of 1.1 × 10 –3 M Ba(NO 3) 2 are added to 80.0 mL of 8.4 × 10 –4 M Na 2CO 3?

erastova [34]

Answer:

A precipitate will form, BaCO₃

Explanation:

When Ba²⁺ and CO₃²⁻ ions are in an aqueous media, BaCO₃(s), a precipitate, is produced following its Ksp expression:

Ksp = 5.1x10⁻⁹ = [Ba²⁺] [CO₃²⁻]

<em>Where the concentrations of the ions are the concentrations in equilibrium</em>

<em />

For actual concentrations of a solution, you can define Q, <em>reaction quotient, </em>as:

Q = [Ba²⁺] [CO₃²⁻]

<em>If Q > Ksp, the ions will react producing BaCO₃, if not, no precipitate will form</em>.

Actual concentrations of Ba²⁺ and CO₃²⁻ are:

[Ba²⁺] = [Ba(NO₃)₂] = 1.1x10⁻³ × (20.0mL / 100.0mL) = 2.2x10⁻⁴M

[CO₃²⁻] = [Na₂CO₃] = 8.4x10⁻⁴ × (80.0mL / 100.0mL) = 6.72x10⁻⁴M

<em>100.0mL is the volume of the mixture of the solutions</em>

<em />

Replacing in Q expression:

Q = [Ba²⁺] [CO₃²⁻]

Q = [2.2x10⁻⁴M] [6.72x10⁻⁴M]

Q = 1.5x10⁻⁷

As Q > Ksp

<h3>A precipitate will form, BaCO₃</h3>

<em />

8 0

3 years ago

Suppose a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O). The total pressure of

julia-pushkina [17]

Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.

<h3>Definition of mole fraction</h3>

The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.

In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:

$mole fraction=\frac{moles of substance}{moles of solution}$

<h3>Mole fraction of O₂ in this mixture</h3>

In this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).

So, the total moles of the solution can be calculated as:

Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)

Then:

Total moles= 4.60 moles + 6 moles

Total moles= 10.60 moles

Finally, the more fraction of O₂ can be calculated as follow:

$Mole fraction of O_{2} =\frac{moles of O_{2}}{total moles}$

$Mole fraction of O_{2} =\frac{4.60 moles}{10.6o moles}$

Solving:

<u><em>Mole fraction O₂ = 0.434</em></u>

Finally, the mole fraction of O₂ in the mixture is 0.434.

Learn more about mole fraction:

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3 0

2 years ago

What is the correct biological term for organisms that are able to manufacture their own food?

almond37 [142]

Answer:

the answer is autotroph

6 0

3 years ago

What is done with nuclear waste?

marusya05 [52]

Answer:

D

Explanation:

4 0

4 years ago

Carbonic acid (H2CO3) is a solution of carbon dioxide in water. Molecules of carbonic acid are not stable. The mixture of carbon

Aleonysh [2.5K]

Le Chatelier's Principle states that the system tries to lower the effect of the newly added change, to maintain equilibrium. In this equation, CO2 and H2O react to form H2CO3, which then dissociates into HCO3^- and an H atom, and then further into CO3^2- and 2 H^+ ions.
If we suddenly add more CO2 molecules into the system, this would cause equilibrium to shift to the right, forming more H2CO3, and consequently, more HCO3^-, CO3^2-, and H^+ ions.

5 0

4 years ago

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