Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
multiplication , addition, subtraction, division
I’m sorry, but how do I see you’re recent questions? I’d love to help! However I have no clue how to find the questions.
R = - 4
t1 = 6
tn = a1*r^(n - 1)
t6 = 6 * (-4)^(6 - 1)
t6 = 6 * (-4)^5
t6 = 6 * (-1024)
t6 = -6144
Answer:
To help in solving exponential equations when relating the bases cannot be used
Step-by-step explanation:
Recall an equation of the form
from the expression
,
is the base and the power is
.
it is impossible to carryout the operation since the bases are not equal.
This is where we implore the help of logarithm which help us to bring the base to a come base i.e using the property below
.
Hence we can conclude that logarithm helps in solving equations when bases cannot easily be related.