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Rasek [7]
3 years ago
7

Please help me please please thank you

Mathematics
1 answer:
OleMash [197]3 years ago
4 0

9514 1404 393

Answer:

  see below

Step-by-step explanation:

The idea is you're trying to find quotient values that get you close to the dividend value when they're multiplied by the divisor.

In the left panel, you are basically looking at 8/3 ≈ 2. Since that is 8 tens, the partial quotient is 2 tens, or 20. The value of that multiplied by the divisor (3) is what gets subtracted from 87 for the next effort.

That difference (27) is the new dividend at the top of the right panel. The line below it (-27) is the result of multiplying the partial quotient by 3. Hence, that partial quotient on the top line must be 9. We want the difference at the bottom of the right panel to be zero.

__

In case you didn't know already that 87/3 = 29, you could work backwards. Starting from 0 at the bottom right, you would fill in the boxes above that, then copy the top box in that panel (27) to the difference at the bottom of the left panel. Of course, the middle number there must be 60 for the difference to be 27. That is 3·20, meaning the partial quotient at left on the top line is 20.

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AABC has vertices at A(1, -9), B(8,0), and C(9,-8).
Rainbow [258]

Check the picture below.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0
3 years ago
Radical 5* radical 2
Setler [38]

Answer:

\sqrt{10}

Step-by-step explanation:

Rule: \sqrt{a} \times \sqrt{b} = \sqrt{ab}

\sqrt{5} \times \sqrt{2} = \sqrt{5 \times 2} = \sqrt{10}

6 0
2 years ago
If the area of a square is 36 inches what is the length of one side?
Pavel [41]
To find the length of a square given the area, we just need to take the square root of the area given. The sqrt of 36 is 6, so each side is 6 inches. :)
4 0
3 years ago
Read 2 more answers
Find the missing side lengths. Leave your answers in simplest radical form.
saveliy_v [14]
ANSWER:
d. x = 15, y= 15√3

EXPLANATION:
This is a special triangle, more specifically a 30-60-90 degree triangle. For sake of not confusing x and y, we will use z to use as our reference for solving this triangle. The side lengths for each angle are as follows:
• 60 degrees = z√3
- this is the value for your y answer
• 30 degrees = z
- this is the value for your x answer
• Hypotenuse = 2z
- this is what we already have

We solve for what we already have which is the Hypotenuse = 30:
2x = 30
x = 15

We now have our x value which is 15.
Now we just plug in that x value for every expression for every angle.

x = 15
y = 15√3

Sorry if I explained it too thoroughly but I’ll be glad to answer any questions or clarifications



8 0
3 years ago
Someone, please help me quick!!
Arte-miy333 [17]
Arc length (L) = 83.7758 ft
7 0
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