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makkiz [27]
3 years ago
6

HELP! A runner is running at a constant 5.51m/s and is 215m in front of another runner who is running at 5.12m/s. If the runner

behind is able to accelerate at a constant 0.100m/s2, determine:
a. How long it takes to overtake the lead runner;
b. Where the passing occurs;
c. How fast the chasing runner is going when they catch the lead runner; and
d. Explain why there are two times that can be calculated in this situation and
how you ruled one of them out.
Physics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

Use the drop-down menus to answer each question.

Which runner finished the 100 m race in the least amount of time?

✔ Ming

Which runner stopped running for a few seconds during the race?

✔ Chloe

At what distance did Anastasia overtake Chloe in the race?

✔ 40 m

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From the things on that list, the copper wire has the least resistance ... unless it happens to be several miles long.
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A microwave has a typical wavelength of about 0.1 meter. What is the comparable wavelength of a radio wave?
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Which force diagram accurately represents a satellite in orbit around Earth?
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First choice

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1) A change in momentum is the result of an
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8 0
4 years ago
A photon detector captures a photon with an energy of 4.29 ✕ 10−19 J. What is the wavelength, in nanometers, of the photon?
serious [3.7K]

Answer :  The wavelength of photon is, 4.63\times 10^{2}nm

Explanation : Given,

Energy of photon = 4.29\times 10^{-19}J

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E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength of photon  = ?

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

4.29\times 10^{-19}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}

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Conversion used : 1nm=10^{-9}m

Therefore, the wavelength of photon is, 4.63\times 10^{2}nm

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