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3 years ago

Solving the following system using the elimination or the substitution method.

Mathematics

1 answer:

Lina20 [59]3 years ago

5 0

Answer and Step-by-step explanation:

For these system of equations, it would be easier to use the substitution method, as we are have one equation that is being equaled to a variable.

Plug the second equation into the value of b for the first equation.

5a + 3(-2a + 3) = 11

Distribute the 3.

5a - 6a + 3 = 11

Simplify.

-a + 3 = 11

Subtract 3 from both sides of the equation.

-a = 8

Divide both sides by -1.

a = -8

Now, we can plug this value into the second equation.

-2(-8) + 3 = b

Multiply -2 and -8 together.

16 + 3 = b

Add together 16 and 3.

19 = b

a = -8

b = 19

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Gary and Joey share a 16-ounce box of cereal. By the end of the week, Gary has eaten 3/8 of the box, and Joey has eaten 1/4 of t

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Answer:

3/8 of the box is left so 6 ounces is left.

Step-by-step explanation:

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Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

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Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

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$324\pi=\pi r^{2}$

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Part 2) we have

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For $r=6\ units$

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$V=\frac{4}{3}\pi (6)^{3}$

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$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$81\pi=\pi r^{2}$

Solve for r

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Answer:

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