Answer and Step-by-step explanation:
For these system of equations, it would be easier to use the substitution method, as we are have one equation that is being equaled to a variable.
Plug the second equation into the value of b for the first equation.
5a + 3(-2a + 3) = 11
Distribute the 3.
5a - 6a + 3 = 11
Simplify.
-a + 3 = 11
Subtract 3 from both sides of the equation.
-a = 8
Divide both sides by -1.
a = -8
Now, we can plug this value into the second equation.
-2(-8) + 3 = b
Multiply -2 and -8 together.
16 + 3 = b
Add together 16 and 3.
19 = b
<u>a = -8</u>
<u>b = 19</u>
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