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zimovet [89]
3 years ago
14

Solving the following system using the elimination or the substitution method.

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

Answer and Step-by-step explanation:

For these system of equations, it would be easier to use the substitution method, as we are have one equation that is being equaled to a variable.

Plug the second equation into the value of b for the first equation.

5a + 3(-2a + 3) = 11

Distribute the 3.

5a - 6a + 3 = 11

Simplify.

-a + 3 = 11

Subtract 3 from both sides of the equation.

-a = 8

Divide both sides by -1.

a = -8

Now, we can plug this value into the second equation.

-2(-8) + 3 = b

Multiply -2 and -8 together.

16 + 3 = b

Add together 16 and 3.

19 = b

<u>a = -8</u>

<u>b = 19</u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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Room occupancy percentage or ROP is A. Total rooms available divided by number of rooms sold B. Room cost divided by room sales
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Answer:

Option D is the correct answer.

Step-by-step explanation:

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Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

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Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

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q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

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Step-by-step explanation:

I have none

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