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vladimir2022 [97]
3 years ago
6

There are 24 adults and 30 children at a science museum

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0
Okay so let’s start by figuring what the total number of people is. To get that we add 24 and 30.
24+30= 54
So we have a total of 54 people.
Now, how many children are there?
30 children... which means the ratio is 30:54

Thirty children to fifty four people total at the museum.

Hope this helps!
Contact me if you have any more questions or concerns.
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Autumn buys eggs and apples at the store.
soldier1979 [14.2K]

Answer:

\frac{(5.76-34.14)}{6}

Step-by-step explanation:

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2 years ago
Find the missing side length of the right triangle shown. Round to the nearest tenth, if
Delvig [45]

Answer:

? = 26 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )

? = \sqrt{676} = 26

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3 years ago
Read 2 more answers
Quadrilateral ABCD is dilated by a scale factor of 1 over 2 centered around (2, 2). Which statement is true about the dilation?
Musya8 [376]

Answer:

Option (1)

1) Segment B'D' will run through (2, 2) and will be shorter than segment BD.

Step-by-step explanation:

The rest of the question is the attached figure (1).

The statement options are:

1) Segment B'D' will run through (2, 2) and will be shorter than segment BD.

2) Segment B'D' will run through (2, 2) and will be longer than segment BD.

3) Segment B'D' will parallel to segment BD and will be shorter than segment BD.

4) Segment B'D' will be parallel to segment BD and will be longer than segment BD.

==============================================================

See the attched figure (2), which represents Quadrilateral ABCD and the image A'B'C'D'

As shown:

The quadrilateral ABCD with vertices A(1,2), B(2,3), C(4,2) and D(2,1).

Quadrilateral ABCD is dilated by a scale factor of 1 over 2 centered around (2, 2).

So,

The quadrilateral A'B'C'D' will be with vertices:

A'= (1.5,2), B'= (2,2.5), C'= (3,2), D'= (2,1.5)

Comparing the options with the figure (2):

So, the answer is option (1)

1) Segment B'D' will run through (2, 2) and will be shorter than segment BD.

6 0
3 years ago
Pls help this question bamboozles me and I am now sitting here confused
UkoKoshka [18]

Answer:

10+3pi

Step-by-step explanation:

The perimeter of of the shaded region is

AC+CT+marcSBT+SA

*Finding AC

The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.

*Finding CT

CT=RT-RC where RC is the width of the rectangle

Also RT is a radius so we have that

CT=6-RC

*Finding marcSBT

The circumference of a whole circle is 2pi*r.

We have a quarter of this with r=6.

1/4*2pi(6)

1/4*12pi

3pi

*Finding SA

SA=RS-AR

RS is a radius of the circle and AR is the length of the rectangle.

So we have that this can be rewritten as

SA=6-AR

Let's put these parts together:

6+6-RC+3pi+6-AR

Simplifying:

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18-8+3pi (Remember length plus width equal 8)

10+3pi

4 0
3 years ago
Limit   
STatiana [176]

Rationalize the numerator:

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This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
4 years ago
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