1. Leave everything alone and don't touch the glass .
2. Tell a Teacher .
3. And that's it .
Destornilladores, alicates de corte diagonal, alicates de punta fina, alicates de bomba ajustable y cinta métrica con punta magnética
The balanced reaction would be as follows:
<span>3NaOH + H3PO4 --> Na3PO4 + 3H20
We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:
</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4?
4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
The mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
Volume = 45.0 L
Temperature = = (87.0 + 273) K = 360 K
Pressure = 950 mm Hg (1 mm Hg = 0.00131579 atm) = 1.25 atm
The formula used to calculate moles is as follows.
∴PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into the above formula as follows:
∴ PV = nRT
=> 1.25 atm × 45.0 L = n × 0.0821 L atm/mol K × 360K
=> n = 1.25 atm × 45.0 L / n × 0.0821 L atm/mol K × 360K
=> n = 56.25 / 29.556 mol
=> n = 1.90 mol
Moles is the mass of a substance divided by its molar mass. So, the mass of Cl₂ (molar mass = 70.906 g/mol) is calculated as follows:
∴ Moles = mass / molar mass
=> 1.90 mol = mass / 70.906 g/mol
=> mass = 134.7214 g
Thus, we can conclude that the mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.
To know more about the Ideal Gas Law :
brainly.com/question/28976906
