Answer:
1) The probability that the mean mpg for a random sample of 25 light vehicles is 0.042341.
2) between 20 and 25 --> 21-25/2.9 = -1.38
Step-by-step explanation:
Problem #1:
- Using the z-score formula, z = (x-μ)/σ/n, where x is the raw score = 20 mpg,μ is the population mean = 21 mpg , σ is the population standard deviation = 2.9, n = random number of samples.
<h3><u>X < 20</u></h3>
- = z = 20 - 21/2.9/√25
- = z = -1/2.9/5
- = z = -1.72414
<h2><u><em>Now</em></u></h2>
<em>P-value from Z-Table:</em>
<h3><u>P(x<20) = 0.042341</u></h3>
Problem #2:
<h3>21-25/2.9 = -1.38</h3>
The way it's written it's
Simplify the following:
7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5
Grouping like terms, 7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5 = 7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5):7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5)
4 X^2 + 2 X^2 = 6 X^2:
7 X^3 + 6 X^2 + (3 X + X) + (2 + 5)
3 X + X = 4 X:
7 X^3 + 6 X^2 + 4 X + (2 + 5)
2 + 5 = 7:Answer: 7 X^3 + 6 X^2 + 4 X + 7
Answer:
The answer is "6 points".
Step-by-step explanation:
This is the answer because it occurs most frequently than the other numbers (It occured 3 times).
B because of the 100 5 are in both so 5/100 is .05
