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KiRa [710]
3 years ago
15

A spacecraft is travelling in space with no resultant force and no resultant moment acting on it​

Physics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

is that a question or a statement lol

Explanation:

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Ingrid kicks a football with an initial velocity at 12 m/s at an angle of 45 relative to the ground
natali 33 [55]
Equation of movement is

y(x) = x * tg (a)  -    \frac{g}{2 * u^{2} * cos (a)^{2} } * x^{2}

where y is y-coordinate, x - x coordinate,  u - your initial speed, a = angle above horizon.

differentiate it to get dy/dx (speed)
 
5 0
4 years ago
A positively-charged object with a mass of 0.129 kg oscillates at the end of a spring, generating ELF (extremely low frequency)
9966 [12]

Answer:308 N/m

Explanation:

Given

mass\left ( m\right )=0.129 kg

wavelength\left ( \lambda \right )=3.86\times 10^7

We know frequency =\frac{c}{\lambda }=\frac{3\times 10^8}{3.86\tmes 10^7}

f=7.772 Hz

As the frequency of radio waves is same as the frequency at which object oscillates

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

7.772=\frac{1}{2\pi }\sqrt{\frac{k}{0.129}}

7.772\times 2\times \pi =\sqrt{\frac{k}{0.129}}

k=307.70\approx 308 N/m

7 0
4 years ago
A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
tensa zangetsu [6.8K]

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

5 0
3 years ago
How much time does it take a trucker to deliver his shipment 480 km away travelling at an average speed of 120 km/hr?​
kifflom [539]

Answer: time=4 hours

Explanation:

formula:

speed = \frac{distance}{time}

time = \frac{distance}{speed}

time= x

speed = 120km/hr

distance = 480 km

x = \frac{480 km}{120km/hr\\}

=\frac{48km*hr}{12km}

cut the zeros

and remove the signs

then

\frac{48}{12} = 4

therefore, time taken to deliver the shipment by trucker is 4 hours

8 0
3 years ago
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

  • When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
  • During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
  • The equilibrium condition will be reached when the following equation be met:

       \Delta Q = c_{st}* m_{A} * (T_{fin}  - T_{0A} ) = c_{st}* m_{B} * (T_{0B}  - T_{fin} )

  • Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for  Tfin, as follows:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\  2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
  • When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
  • So, option b) is the right one.
8 0
3 years ago
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