Answer:
0.02 m
Explanation:
R₁ = initial distance jumped by jumper = 7.4 m
R₂ = final distance jumped by jumper = ?
θ₁ = initial angle of jump = 45°
θ₂ = final angle of jump = 42.9°
= speed at which jumper jumps at all time
initial distance jumped is given as
final distance jumped is given as
Dividing final distance by initial distance
distance lost is given as
d =
d = 7.4 - 7.38
d = 0.02 m
Answer:
The speed of car leaves Vernonville = 45 miles per hour
The speed of car leaves Salem = 55 miles per hour
Explanation:
Given that distance between Salem and Vernonville = 160 miles
Lest take speed of car which leaves from Vernonville = V miles per hour
So the speed of car which leaves from Salem = V +10 miles per hour
These two car meet at time = 1 hr 36 min = 1.6 hr
Distance travel by car leaves from Salem = x
x= (V+10) x 1.6 --------1
Distance travel by car leaves from Vernonville = 160 - x
160 - x= V x 1.6 ----------2
From equation 1 and 2
160 - (V+10) x 1.6 = V x 1.6
V= 45 miles per hour
So
The speed of car leaves Vernonville = 45 miles per hour
The speed of car leaves Salem = 55 miles per hour
