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Leya [2.2K]
3 years ago
6

The velocity of an object is the distance it travels per unit time. Suppose the velocity of a gilding bird is measured to be 52.

Cm/s. Calculate the time it will take the bird to travel 3.7 m. Be sure your answer has a unit symbol and the correct number of significant digits.
Physics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

d=7.115s

Explanation:

What problem says can be written mathematically as:

v=\frac{d}{t}

Where:

v=Velocity\\t=Time\\d=Distance

The problem itself it's really simple, we only need to replace the data provided in the previous equation, but first, let's convert the units of the velocity from cm/s to m/s because we have to work with the same units and working in meters is the most apropiate action, because is the base unit of length in the International System of Units:

52\frac{cm}{s} *\frac{1m}{100cm} =0.52\frac{m}{s}

Now, we can replace the data in the equation and find the time it will take the bird to travel 3.7 m:

0.52=\frac{3.7}{t}

Solving for t, multiplying by t both sides, and dividing by 0.52 both sides:

t=\frac{3.7}{0.52} =7.115384615s\approx7.115s

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Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V

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In order to calculate the cutoff wavelength we have to consider that Ek=0

in this case  h*ν=W

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λ= (h*c)/4.52 eV

λ= (1240 eV*nm)/(4.52 eV)=274.34 nm

From this h*ν = Ek+W;  we can calculate the kinetic energy for a radiation wavelength of 198 nm

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Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this  acts to slow down the ejected electrons from the catode.

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Explanation:

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