DISPLACEMENT WITH CONSTANT ACCELEration. Given information: displacement=64m, acceleration=9.81m\s and time interval=3s. calcula
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The density of the gold is calculated to be "19,300 kg/m³".
<u>Explanation:</u>
Given:
Volume = 2cm³
Mass = 38.6 grams.
To Find:
Density of the gold = ?
Solution:
Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.
Mass in grams is converted into kg as,
1 g = 0.001 kg
38. 6 g =
Now we have to convert cm³ to m³ as,
1 cm³ = 10⁻⁶ m³
2 cm³ = 2 × 10⁻⁶ m³
So Density =
Physical properties of Gold:
- Gold is a heavy metal.
- It is Malleable and ductile.
- It is a corrosion resistant element.