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4 years ago

What is the oxidation state of rubidium (Rb)?

Physics

1 answer:

Ostrovityanka [42]4 years ago

3 0

Answer:

The answer is rubidium exhibits +1 and -1 oxidation states.

Explanation:

Rubidium is a reactive element and belongs to the group 1 of the periodic table. It is an alkali metal and it is a highly reactive element.

Rubidium is a very soft and white lustrous element. Rubidium has +1 and -1 oxidation states. When rubidium is burnt, it forms oxides, superoxides and peroxides respectively.

For example, in rubidium oxide (Rb2O), Rubidium has a +1 oxidation state. While in peroxides rubidium exhibits -1 oxidation state. For example Rubidium peroxides (Rb2O2).

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What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?

maks197457 [2]

Answer:

Wavelength = 1.36 * 10^{-34} meters

Explanation:

Given the following data;

Mass = 0.113 kg

Velocity = 43 m/s

To find the wavelength, we would use the De Broglie's wave equation.

Mathematically, it is given by the formula;

$Wavelength = \frac {h}{mv}$

Where;

h represents Planck’s constant.

m represents the mass of the particle.

v represents the velocity of the particle.

We know that Planck’s constant = 6.6262 * 10^{-34} Js

Substituting into the formula, we have;

$Wavelength = \frac {6.6262 * 10^{-34}}{0.113*43}$

$Wavelength = \frac {6.6262 * 10^{-34}}{4.859}$

Wavelength = 1.36 * 10^{-34} meters

7 0

3 years ago

The change in momentum of an object is equal to the Question 4 options: Force acting on it times its velocity. impulse acting on

lesya [120]

Answer:

impulse acting on it

Explanation:

The impulse is defined as the product between the force applied to an object (F) and the time interval during which the force is applied ( $\Delta t$ ):

$I=F\Delta t$

We can prove that this is equal to the change in momentum of the object. In fact, change in momentum is given by:

$\Delta p = m \Delta v$

where m is the mass and $\Delta v$ is the change in velocity. Multiplying and dividing by $\Delta t$ , we get

$\Delta p = m \frac{\Delta v}{\Delta t} \Delta t$

and since $\frac{\Delta v}{\Delta t}$ is equal to the acceleration, a, we have

$\Delta p = ma \Delta t$

And since the product (ma) is equal to the force, we have

$\Delta p = F \Delta t$

which corresponds to the impulse.

5 0

3 years ago

A projectile lands at the same height from which it was launched. which initial velocity will result

Serhud [2]

The required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

First, we must understand that the component of the velocity along the vertical is due to maximum height achieved and expressed as usin θ.

The component of the velocity along the horizontal is due to the range of the object and is expressed as ucosθ.

If the <u>air resistance is ignored</u>, the velocity of the object will be constant throughout the flight and the initial velocity will be equal to the final velocity.

Hence the required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

Learn more here; brainly.com/question/12870645

5 0

3 years ago

What damage a tornado can cause

Ksivusya [100]

Alrighty, so, houses can be destroyed, people can be killed, animals can be killed, habitats can be destroyed, and trees can be uprooted. Tornadoes can create massive damage.

Hope this helps! (:

5 0

3 years ago

a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its potential energy (PE) when it is 2.00 m above the grou

zmey [24]

Answer:

1.56 J

Explanation:

The potential energy only depends on the vertical height from the ground level.

We consider the ground level to have zero P.E.

So when it is 2 m above the ground level,

P.E. = mgh

= 0.078×10×2

= 1.56 J

7 0

4 years ago