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Volgvan
4 years ago
8

What is the oxidation state of rubidium (Rb)?

Physics
1 answer:
Ostrovityanka [42]4 years ago
3 0

Answer:

The answer is rubidium exhibits +1 and -1 oxidation states.

Explanation:

Rubidium is a reactive element and belongs to the group 1 of the periodic table. It is an alkali metal and it is a highly reactive element.

Rubidium is a very soft and white lustrous element. Rubidium has +1 and -1 oxidation states. When rubidium is burnt, it forms oxides, superoxides and peroxides respectively.

For example, in rubidium oxide (Rb2O), Rubidium has a +1 oxidation state. While in peroxides rubidium exhibits -1 oxidation state. For example Rubidium peroxides (Rb2O2).

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There are 2.2 pounds in a kilogram. If a boy's mass is 40 kg, what is his weight in pounds?
kifflom [539]
Hey There! :)

40*2.2
=88

Hope this helps.
-Benjamin
3 0
4 years ago
Read 2 more answers
An opera singer in a convertible sings a note at 600 Hz while cruising down the highway at 90km/hr. What is the frequency heard
Inessa05 [86]

Answer:

f=647.17Hz

Explanation:

Given data

Frequency fs=600 Hz

Velocity Vs=90 km/hr =25 m/s

Speed of sound v=343 m/s

To find

Frequency f heard by a person standing beside the road in front of the car

Solution

From Doppler's effect we know that:

f=f_{s}(\frac{v+vL}{v+vs} )\\ as\\vL=0

Here Vs is negative as the source is moving towards listener

f=fs(\frac{v+0}{v-vs} )\\f=(600Hz)(\frac{343m/s+0}{343m/s-25m/s} )\\f=647.17Hz  

5 0
4 years ago
How does Scientific theories differ from scientific laws
finlep [7]
Hey there!

\ggg \ scientific \ laws : Scientific law's would be a law that was proven and test and examined by scientist.These laws would basically be fact's, proven that what ever they say would technically be true.

\ggg \ Scientific \ theories: These are "theories" that are made by scientist usually hypothesis to see what law would actually be true. These "theories" are of course not true, they are not quite laws, they are experiment's that could be laws, but they're theories, thing's that are technically false.

Hope this helps you!
7 0
4 years ago
A uniform rod of mass M and length L can pivot freely at one end. Initially, the rod is oriented vertically above the pivot, in
Leya [2.2K]

Answer:

The speed of its center of mass =\sqrt{\frac{3}{2}gL}

Explanation:

Consider the potential energy at the level of center of mass of rod below the pivot=0

Mass of uniform rod=M

Length of rod=L

The rotational inertia about the end of a uniform rod=\frac{1}{3}ML^2

Kinetic energy at the level of center of mass of rod below the pivot=\frac{1}{2}I\omega^2

Kinetic energy at the level of center of mass of rod above the pivot=0

Potential energy at the level of center of mass of rod above the pivot=mgh

We have to find the center of mass ( in terms of g and L).

According to conservation of law of energy

Initial P.E+Initial K.E=Final P.E+Final K.E

mgh+0=0+\frac{1}{2} I\omega^2

Where K.E=\frac{1}{2} I\omega^2

I=Moment of inertia

\omega=Angular velocity

Substitute the values then we get

MgL=\frac{1}{2}\times \frac{1}{3}ML^2\omega^2

\omega^2=\frac{6g}{L}

Now, we know that \omega=\frac{v}{r}, r=\frac{L}{2}

Substitute the values then we get

\frac{v^2}{(\frac{L}{2})^2}=\frac{6g}{L}

\frac{v^24}{L^2}=\frac{6g}{L}

v^2=\frac{6g\times L^2}{4L}

v^2=\frac{3gL}{2}

v=\sqrt{\frac{3}{2}gL}

Hence, the speed of its center of mass =\sqrt{\frac{3}{2}gL}

4 0
4 years ago
How much work is needed to stop a 1,110 kg car that is moving straight down the
schepotkina [342]

Answer:

382.74 kJ.

Explanation:

The work that must be done to stop an 1100 kg car travelling at 59  km/h is  - 382.74 kJ.

3 0
3 years ago
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