Do u have an attachment maybe??
Answer:
Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<h3>y=-4x-9 and y=-4x-1</h3>
First, you have to substitute of y=-4x-1.
![\Longrightarrow: \sf{[-4x-1=-4x-9]}](https://tex.z-dn.net/?f=%5CLongrightarrow%3A%20%5Csf%7B%5B-4x-1%3D-4x-9%5D%7D)
<u>Add by 4x from both sides.</u>
<u>Solve.</u>
- <u>Therefore, the correct answer is "D. No solution".</u>
I hope this helps. Let me know if you have any questions.
In order to solve this, you have to plug in all of the costs of the gifts and add them, which in all equals $36. since jim only has 1/4 of the money he needs to buy the gifts, you need to divide 36 by 4. this gives you 9, so now you know he has 9 dollars.
and to find out how much more money he needs, you can subtract 9 from 36 which represents a fourth of the required money. the answer is 27, that's how much jim needs in order to buy his gifts.
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
brainly.com/question/15019502
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