Answer:
2.19moles
Explanation:
mole = mass ÷ molar mass
Molar Mass of the compound, C135H96O9NS =
12(135) + 1(96) + 16(9) + 14 + 32
= 1620 + 96 + 144 + 14 + 32
= 1906g/mol
Next, we calculate the mass percent of Oxygen in the compound
O9 = 16(9) = 144g/mol
144/1906 × 100
= 0.0755 × 100
= 7.55%
This means that there are 0.0755g of Oxygen in 1 mole of the coal compound.
Hence, in 29.1 moles of coal, there would be 29.1 × 0.0755
= 2.19moles of Oxygen
