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11111nata11111 [884]
3 years ago
10

The process in which an organic acid and an alcohol react to form an ester and water is known as esterification. Ethyl butanoate

(C3H7COOC2H5) an ester is formed when the alcohol ethanol (C2H5OH) and butanoic acid (C3H7COOH) are heated in the presence of sulfuric acid.C2H5OH(l) + C3H7COOH(l) C3H7COOC2H5(l) + H2O(l)Determine the mass of ethyl butanoate produced if 6.00 mol of ethanol is used.
Chemistry
1 answer:
egoroff_w [7]3 years ago
7 0

Answer:

697 g

Explanation:

Ethanol (C₂H₅OH) and butanoic acid (C₃H₇COOH) react to form ethyl butanoate (C₃H₇COOC₂H₅) and water (H₂O).

C₂H₅OH + C₃H₇COOH → C₃H₇COOC₂H₅ + H₂O

The molar ratio of C₂H₅OH to C₃H₇COOC₂H₅ is 1:1. The moles of C₃H₇COOC₂H₅ produced from 6.00 moles of C₂H₅OH are:

6.00 mol C₂H₅OH × (1 mol C₃H₇COOC₂H₅/1 mol C₂H₅OH) = 6.00 mol C₃H₇COOC₂H₅

The molar mass of C₃H₇COOC₂H₅ is 116.16 g/mol. The mass corresponding to 6.00 mol is:

6.00 mol × (116.16 g/mol) = 697 g

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marusya05 [52]

Hello!

Your answer is A, asthenosphere

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It is <u>below the lithosphere,</u> between <u>80 and 200 km</u> below the surface.

Therfore, the asthenosphere is <u>the part of the mantle that is still a solid but flows like a thick, heavy liquid.</u>

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4 years ago
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A chemical reaction was carried out three times. The mass of the product was 8.93 g for the first trial, 8.94 g for the second t
joja [24]

The three mass value measure are precise mass

<u>explanation</u>

precise mass is term use to describe data from experiment that have  been repeated several times. An experiment that yield tightly grouped  set of data it has a high precision.  8.93 , 8.94  and 8.92 are precise mass since they have repeated severally

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For a particular experiment, Nadia must measure the following quantities:
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How much (Q) heat is needed to melt 35 g of iodine? Hf = 61.7 J/g.
aev [14]

Taking into account the definition of calorimetry and latent heat, a heat of 2159.5 J is needed to melt 35 g of iodine.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

<h3>Heat needed to melt iodine</h3>

In this case, you know:

  • m= 35 g
  • L=61.7 \frac{J}{g}

Replacing in the definition of latent heat:

Q= 35 g× 61.7 \frac{J}{g}

Solving:

<u><em>Q=2159.5 J</em></u>

Finally, a heat of 2159.5 J is needed to melt 35 g of iodine.

Learn more about calorimetry:

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8 0
2 years ago
A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams
jek_recluse [69]

The mass of methanol produced is 8.0 g.

We have the masses of two reactants, so this is a <em>limiting reactant</em> problem.

We know that we will need a <em>balanced equation</em> with masses, moles, and molar masses of the compounds involved.

<em>Step 1</em>. <em>Gather all the informatio</em>n in one place with molar masses above the formulas and everything else below them.

MM: ___28.01  2.016 ___32.04

_______CO + 2H_2 → CH_3OH

Mass/g: 7.0 __2.5

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>

Moles of CO = 7.0 g CO × (1 mol CO/28.01g CO) = 0.250 mol CO

Moles of H_2 =2.5 g H_2 × (1 mol H_2/2.016 g H_2) = 1.24 mol H_2

<em>Step 3. </em>Identify the<em> limiting reactan</em>t

Calculate the <em>moles of CH_3OH</em> we can obtain from each reactant.

<em>From CO</em>: Moles of CH_3OH = 0.250 mol CO  × (1 mol CH_3OH /1 mol CO)

= 0.250 mol CH_3OH

<em>From H_2</em>: Moles of CH_3OH = 1.24 mol H_2 × (1 mol CH_3OH /2 mol H_2)

= 0.620 mol CH_3OH

<em>CO is the limiting reactant</em> because it gives the smaller amount of CH_3OH.

<em>Step 4</em>. Calculate the <em>mass of CH_3OH</em>

Mass of CH_3OH = 0.250 mol CH_3OH × (32.04 g CH_3OH /1 mol CH_3OH) = 8.0 g CH_3OH

3 0
3 years ago
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