Answer:
Efficiency of the machine = 75%
Explanation:
Given:
Input work = 8,000 J
Output work = 6,000 J
Find:
Efficiency of the machine
Computation:
Efficiency of the machine = [Output work / Input work]100
Efficiency of the machine = [6,000 / 8,000]100
Efficiency of the machine = 75%
Answer:
Total distance covered (scalar quantity) = 23 km
Displacement (vector quantity) = 3 km north from the original starting point
Explanation:
Since he drove 13 km north and then 10 km south, the total distance he cover in his drive was: 13 km + 10 km = 23 km
On the other hand, his displacement was 3 km north from where he started.
The distance between the two cities is 513.24 km.
<h3>Time of motion when the two trains meet</h3>
The time spent on the journey when the two trains meet is calculated as follows;
(Va - Vb)t = d
where;
- d is the distance between the trains before meeting
(76 - 65)t = 40
11t = 40
t = 40/11
t = 3.64 hr
<h3>Distance traveled by the fast train</h3>
d1 = 76 km/h x 3.64 h
d1 = 276.64 km
<h3>Distance traveled by the slow train</h3>
d2 = 65 km/h x 3.64 h
d2 = 236.6 km
The distance between the two cities = 276.64 km + 236.6 km
= 513.24 km
Learn more about relative velocity here: brainly.com/question/17228388
Answer:
option d)
Explanation:
The amount of heat required to convert the 1 g of ice at 0 degree C to 1 g water at 0 degree C is called latent heta of fusion.
H = m Lf
where,, h is the heat required, m is the mass and Lf is the latent heat of fusion
1140 = m x 79.7
m = 14.3 g
Answer:
equivalent power = 6.60 × 
W
Explanation:
given data
coal train length = 1.5 km = 1500 m
contain = 120 cars
holding= 110 tonnes of coal each
train traveling speed = 100 km/h = 27.78 m/s
to find out
equivalent power in watts
solution
we take here energy produce by coal is 27 × 
J/kg
and here total coal = 120 × 110 × 10³ kg
sop here energy produce by total coal is
energy produce by total coal = 27 × × 120 × 110 × 10³
and time required to cross that distance is
time = 
time = 
time = 53.99 sec
so here equivalent power will be
equivalent power = 
equivalent power = 
equivalent power = 6.60 × W
