Answer:
The total number of students in a survey is 300.
Let the number of junior male(JM) be x and the number of senior males(SM) be y.
Let the number of junior female(JF) be p and the number of senior males(SF) be q.
It is given that there are 160 males, 80 junior females, 130 seniors.
Since number of males are 160. So the number of females are,
Since number of junior females is 80.
Since number of seniors are 130.
Since number of males is 160.
Therefore, the table and venn diagram is shown below.
Answer:
Gradient of A: 2
Gradient of B: -1
Step-by-step explanation:
Gradient = change in y/change in x
✔️Gradient of A using two points on line A, (2, 5) and (0, 1):
Gradient = (1 - 5)/(0 - 2) = -4/-2
Simplify
Gradient of A = 2
✔️Gradient of B using two points on line B, (0, 5) and (5, 0):
Gradient = (0 - 5)/(5 - 0) = -5/5
Simplify
Gradient of B = -1
Answer:
Step-by-step explanation:
9x⁴ – 2x² – 7 = 0
Let's say that u = x²:
9u² – 2u – 7 = 0
Factor:
(u – 1) (9u + 7) = 0
u = 1, -7/9
Since u = x²:
x² = 1, -7/9
x = ±1, ±i √(7/9)
Answer:
DC = 2
Step-by-step explanation:
The wrong equation was used.
The right equation to use based on the midsegment theorem of a trapezoid is:
MN = ½(AB + DC)
MN = 8
AB = 14
Substitute
8 = ½(14 + DC)
Multiply both sides by 2
8*2 = ½(14 + DC)*2
2*8 = 14 + DC
16 = 14 + DC
16 - 14 = 14 + DC - 14
2 = DC
DC = 2
Answer:
Meters:4.8x10 to the 6th power
Millimeters:4.8x 9th power.
Be doin Pearson MathXL
I did 1 today.
