The following are the steps involved in drawing Lewis structure of the polyatomic trisulfide anion :
Total number of valence electrons =
Resonance is not possible in this ion. The molecular geometry of the ion will be bent as there are two lone pairs and two bond pairs on the central atom.
<u>Answer:</u> The correct answer is Option D.
<u>Explanation:</u>
To calculate the hybridization of , we use the equation:
where,
V = number of valence electrons present in central atom (S) = 6
N = number of monovalent atoms bonded to central atom = 0
C = charge of cation = 0
A = charge of anion = 0
Putting values in above equation, we get:
The number of electron pair around the central metal atom are 3. This means that the hybridization will be and the electronic geometry of the molecule will be trigonal planar.
Hence, the correct answer is Option D.
Answer:
A. c. Keq=[H2]^2[S2]/[H2S]^2
B. b. Keq=[COCl2]/[CO][Cl2]
Explanation:
Hello,
In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:
A. For the reaction:
The equilibrium expression is:
Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.
B. For the reaction:
The equilibrium expression is:
Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].
Regards.