Addition Polymerization reaction also known as chain Polymerization reaction. Monomers must contain double bond as a functional group.
<h3>What is Polymerization Reaction? </h3>
The chemical reaction which involves the addition of monomers to form higher molecular mass molecules is known as polymerization. There are two basically two types of polymerization, one is chain-reaction (or addition) and the other is step-reaction (or condensation) polymerization.
<h3>Chain-reaction (addition) polymerization</h3>
One of the most common and important types of polymer reactions is chain-reaction (addition) polymerization. This type of polymerization involves three step process including two chemical entities. The first which is known simply as a monomer. It is initially exists as simple units. Normally in all cases, the monomers must have at least one carbon-carbon double bond. Ethylene is one of the best known example of a monomer which is used to make a common polymer.
<h3>
Step-reaction (condensation) polymerization </h3>
It is second type of polymerization reaction. This polymerization method is used to produce polymers having lower molecular weight as compared to chain reactions and requires higher temperatures to occur.
In this type of reaction, monomers must have two functional group.
Thus, we concluded that the Monomers must contain double bond as a functional group in addition Polymerization reaction.
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Answer: (a) pH = 4.774, (b) pH = 4.811 and (c) pH = 4.681
Explanation: (a) pH of the buffer solution is calculated using Handerson equation:
pKa for acetic acid is 4.76. concentration of base and acid are given as 0.95M and 0.92M. Let's plug in the values in the equation and calculate the pH of starting buffer.
pH = 4.76 + 0.014
pH = 4.774
(b) When 0.040 mol of NaOH (strong base) are added to the buffer then it reacts with 0.040 mol of acetic acid and form 0.040 mol of sodium acetate.
Original buffer volume is 1.00 L. So, the original moles of sodium acetate will be 0.95 and acetic acid will be 0.92.
moles of acetic acid after addition of NaOH = 0.92 - 0.040 = 0.88
moles of sodium acetate after addition of NaOH = 0.95 + 0.040 = 0.99
Let's again plug in the values in the Handerson equation:
pH = 4.76 + 0.051
pH = 4.811
(c) When 0.100 mol of HCl are added then it reacts with exactly 0.100 moles of sodium acetate(base) and form 0.100 moles of acetic acid(acid).
so, new moles of acetic acid = 0.92 + 0.100 = 1.02
new moles of sodium acetate = 0.95 - 0.100 = 0.85
Let's plug in the values in the equation:
pH = 4.76 - 0.079
pH = 4.681
I don’t know but you can try it
