A -0.00325 C charge q1 is placed 5.62 m from a second charge q2. The first charge is repelled with a 48900 N force. What is the
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Answer:
<em>The thermal energy dissipated in A would be twice that in B</em>
Explanation:
Resistor B (RB)= R
Resistor A (RA)= 2 R
When they are connected in series the equivalent Resistance in the circuit would be;
Equivalent resistance = RA +RB = R + 2 R = 3 R;
From ohms law I = V/R
I = V/3 R
Now the thermal energy is the power dissipated by the circuit and can be obtained thus;
P =
Then,
Therefore Pa : Pb = 2: 1, this means that the thermal energy dissipated in A would be twice that in B
The velocity when function p(t)=11 is 8 .
According to the question
The position of a car at time t represented by function :
Now,
When function p(t) = 11 , t will be
11 = t²+2t-4
0 = t² + 2t - 15
or
t² +2t-15 = 0
t² +(5-3)t-15 = 0
t² +5t-3t-15 = 0
t(t+5)-3(t+5) = 0
(t-3)(t+5) = 0
t = 3 , -5
as t cannot be -ve as given ( t≥0)
so,
t = 3
Now,
the velocity when p(t)=11
As we know velocity =
therefore to get the value of velocity from function p(t)
we have to differentiate the function with respect to time
v(t) = 2t + 2
where v(t) = velocity at that time
as t = 3 for p(t)=11
so ,
v(t) = 2t + 2
v(t) = 2*3 + 2
v(t) = 8
Hence, the velocity when function p(t)=11 is 8 .
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