Answer:
Simple! The answer is yes.
Step-by-step explanation:
Simply put the equations into Desmos graphing calculator and it will show you that the equations are parallel. :))
Square (added characters)
Step-by-step explanation:
1. The first graph has a negative slope (increases to the left) and has a y-intercept of 3. So, the equation of the line would be y = -2x + 3.
2. The second graph has a positive slope (increases to the right) and has a y-intercept of -3. Therefore, the equation of the line would be y = 2x - 3.
3. The third graph has a negative slope and has a y-intercept of -3. So, we can say that the equation of the line would be y = -2x - 3.
4. The fourth graph has a positive slope and a y-intercept of 3. Therefore, the equation of the line would be y = 2x + 3.
False, a negetive and negetinve both equal positive
Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
