Answer:
Tyrosine is a polar and aromatic compound. its side chain acidity and basicity is neutral
if a peptide contain only a string of tyrosine residue especially l tyrosine the solubility increases more
Explanation:
even tyrosine number remains constant, tyrosine containing peptide will be more soluble. This peptide is soluble in 1 M HCl (100 mg/ml), with heating. The solubility in water (25 °C) is 0.45 mg/ml in the pH range 3.2 - 7.5.
2.0 mg/ml; at pH 9.5, the solubility is 1.4 mg/ml; and at pH 10, the solubility is 3.8 mg/ml.
3 mol H₂ → 2 mol NH₃
5 mol H₂ → x mol NH₃
x=2*5.0/3=3.3
n(NH₃)=3.3 mol
0 because you would be floating at the top within seconds and also have fun with the sudden stop
Solution..
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Let's calculate the mass of CO₂.
We have (12+(16*2))
= 12+32
=44gmol¯¹..
a. What is the percent by mass of carbon?
Mass of carbon /mass of CO₂ × 100%
12/44 × 100%
=27.3%...
b. What is the percent by mass of oxygen?
Mass of oxygen/mass of CO₂ × 100%
(2×16)/44 × 100%
32/44 × 100%
=72.7%....
To check.. You'll add this two percentage compositions together and see of it gives 100%... If it does then we're good...
27.3%+72.7% = 100%.... Checked..
Hope this helped....?
Answer: determine how they break
Explanation:
hope this helps!
