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3 years ago

How many grams of Ca metal are produced by the electrolysis of molten CaBr2 using a current of 30.0 amp for

Chemistry

1 answer:

Vanyuwa [196]3 years ago

4 0

Answer: 123 g

Explanation: Q =It = nzF. For Ca^2+ z= 2, t = 5.5 x 3600 s and I = 30.0

And F= 96485 As/mol

Amount of moles is n = It /zF = 3.078 mol , multiply with atomic mass 40.08 g/mol

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Miguel’s family drove 357 miles on their weekend trip. Their car’s average gas mileage was 25.5 miles per gallon. How many gallo

ad-work [718]

Answer:

14 gallons

Explanation:

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6 0

3 years ago

Read 2 more answers

A gas mixture with a total pressure of 745 mmHg contains each of the following gases at the indicated partial pressures: CO2, 24

Setler79 [48]

Answer:

For Part A: The partial pressure of Helium is 218 mmHg.

For Part B: The mass of helium gas is 0.504 g.

Explanation:

For Part A:

We are given:

$p_{CO_2}=245mmHg\\p_Ar}=119mmHg\\p_{O_2}=163mmHg\\P=745mmHg$

To calculate the partial pressure of helium, we use the formula:

$P=p_{CO_2}+p_{Ar}+p_{O_2}+p_{He}$

Putting values in above equation, we get:

$745=245+119+163+p_{He}\\p_{He}=218mmHg$

Hence, the partial pressure of Helium is 218 mmHg.

For Part B:

To calculate the mass of helium gas, we use the equation given by ideal gas:

PV = nRT

or,

$PV=\frac{m}{M}RT$

where,

P = Pressure of helium gas = 218 mmHg

V = Volume of the helium gas = 10.2 L

m = Mass of helium gas = ? g

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

T = Temperature of helium gas = 283 K

Putting values in above equation, we get:

$218mmHg\times 10.2L=\frac{m}{4g/mol}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 283K\\\\m=0.504g$

Hence, the mass of helium gas is 0.504 g.

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3 years ago

How are protons, electrons, and neutrons correctly compared

Fiesta28 [93]

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3 years ago

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mylen [45]

Answer:

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Explanation:

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3 years ago

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lakkis [162]

Answer:

The ionic bond present between CaO molecule

Explanation:

7 0

2 years ago