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USPshnik [31]
3 years ago
11

How many grams of Ca metal are produced by the electrolysis of molten CaBr2 using a current of 30.0 amp for

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer: 123 g

Explanation: Q =It = nzF. For Ca^2+ z= 2, t = 5.5 x 3600 s and I = 30.0

And F= 96485 As/mol

Amount of moles is n = It /zF = 3.078 mol , multiply with atomic mass 40.08 g/mol

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Double replacement i believe
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4. Solve the following heat flow problem, being sure to show all your work (you may either type your
Viktor [21]

Answer:

0.70 J/g.°C

Explanation:

Step 1: Given data

  • Mass of graphite (m): 402 g
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  • Initial temperature: 26°C
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  • Specific heat of graphite (c): ?

Step 2: Calculate the specific heat of graphite

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1136 J / 402 g × (30°C - 26°C)

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3 years ago
Which statements describe how heat flows in foil?
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Answer: c

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In this experiment, we will be performing a titration with a buret. place the steps in order. 1. record the ph when 0.0 ml of na
77julia77 [94]

I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

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2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.

3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.

4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.

5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).

6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.

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3 years ago
14 km is how many centimeters?
Yuki888 [10]

Answer:

1400000 cm

Explanation:

14 km equals to 1400000 cm (14 km = 1400000 cm)

PLEASE MARK ME AS THE BRAINLIEST...   ;)

8 0
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