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BlackZzzverrR [31]
3 years ago
13

A sample of the amino acid tyrosine is barely soluble in water. Would a peptide containing only a string of Tyr residues be more

or less soluble, assuming the total number of Tyr groups remains constant? Explain.
Chemistry
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

Tyrosine is a polar and aromatic compound. its side chain acidity and basicity is neutral

if a peptide contain only a string of tyrosine residue especially l tyrosine the solubility increases more

Explanation:

even tyrosine number remains constant, tyrosine containing peptide will be more soluble. This peptide is soluble in 1 M HCl (100 mg/ml), with heating. The solubility in water (25 °C) is 0.45 mg/ml in the pH range 3.2 - 7.5.

2.0 mg/ml; at pH 9.5, the solubility is 1.4 mg/ml; and at pH 10, the solubility is 3.8 mg/ml.

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What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol
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Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 63 g * 1 mol/(58.44 g)

moles of NaCl = 1.078 moles

Finally we can find the molarity of the solution

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Answer: the molarity of the solution is 1.66 M.

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