A sample of the amino acid tyrosine is barely soluble in water. Would a peptide containing only a string of Tyr residues be more
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Answer:
11.9 is the pOH of a 0.150 M solution of potassium nitrite.
Explanation:
Solution : Given,
Concentration (c) = 0.150 M
Acid dissociation constant =
The equilibrium reaction for dissociation of (weak acid) is,
initially conc. c 0 0
At eqm.
First we have to calculate the concentration of value of dissociation constant .
Formula used :
Now put all the given values in this formula ,we get the value of dissociation constant .
By solving the terms, we get
No we have to calculate the concentration of hydronium ion or hydrogen ion.
Now we have to calculate the pH.
pH + pOH = 14
pOH =14 -2.1 = 11.9
Therefore, the pOH of the solution is 11.9