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BlackZzzverrR [31]
3 years ago
13

A sample of the amino acid tyrosine is barely soluble in water. Would a peptide containing only a string of Tyr residues be more

or less soluble, assuming the total number of Tyr groups remains constant? Explain.
Chemistry
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

Tyrosine is a polar and aromatic compound. its side chain acidity and basicity is neutral

if a peptide contain only a string of tyrosine residue especially l tyrosine the solubility increases more

Explanation:

even tyrosine number remains constant, tyrosine containing peptide will be more soluble. This peptide is soluble in 1 M HCl (100 mg/ml), with heating. The solubility in water (25 °C) is 0.45 mg/ml in the pH range 3.2 - 7.5.

2.0 mg/ml; at pH 9.5, the solubility is 1.4 mg/ml; and at pH 10, the solubility is 3.8 mg/ml.

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Answer:

The mass of the surrounding is M_t = 263.9 \ g

Explanation:

From the question we are told that

      The mass of  NaOH is  m = 13.9 \ g

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The mass of the surround here is the mass of the coffee-cup calorimeter and this contain the mixture ( water and the NaOH ) so the mass of the surrounding is  

  M_t = 263.9 \ g

       

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